how to get the starting text and ending text from image path in python using regex?

Question

Here is the given two scenarios

Example 1

the Image Path is https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here
and the url was this and Click here to view the detail goes here

Example 2

https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here
Click here to view screenshot the detail goes here

My Code is Given Below

import re
 str_text = "the Image Path is https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here and the url was this and Click here to view the detail goes here"
urls = re.findall('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+', str_text)
print("Urls: ",":".join(urls))

Result

https://ictagrisindh.gov.pk/img/inauguration1.jpg

i want to extract the text from starting point to end point between & also extract text from everywhere in image path

Any Help would be appreciated & thanks in Advance

Answer 1

import re

e1 = 'the Image Path is https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here' + \
'and the url was this and Click here to view the detail goes here'

e2 = 'https://ictagrisindh.gov.pk/img/inauguration1.jpg the detail goes here' + \
'Click here to view screenshot the detail goes here'

start_pattern = '(^.+)(?=http.+.jpg)'
image_url_pattern = '(http.+.jpg)'
end_pattern = '(?:^.+.jpg)(.+$)'

start = re.findall(start_pattern, e1)
url = re.findall(image_url_pattern, e1)
end = re.findall(end_pattern, e1)

print(f'start: {start}')
print(f'url: {url}')
print(f'end: {end}')

Example 1:

start: ['the Image Path is ']
url: ['https://ictagrisindh.gov.pk/img/inauguration1.jpg']
end: [' the detail goes hereand the url was this and Click here to view the detail goes here']

Example 2:

start: []
url: ['https://ictagrisindh.gov.pk/img/inauguration1.jpg']
end: [' the detail goes hereClick here to view screenshot the detail goes here']