How to go to Launcher screen when home button is clicked in application's white screen?

Question

I have an application where in onCreate() function heavy operation is performed. Thus when we launched an application, it displays white screen and then display the webview.

Now client pressed the home screen when white screen is displayed. In this scenario, launcher is not displayed. The page is still in white screen.

In log,

05-04 17:36:06.237  2841 16533 I WindowManager: Not displayed: s=Surface(name=com.android.launcher/com.android.launcher3.Launcher)/@0x228707a pv=true mDrawState=1 ph=false th=false a=true     

I have framework source code,

path: frameworks/base/services/core/java/com/android/server/wm/AppWindowToken.java                  
                    
                   
  boolean updateDrawnWindowStates(WindowState w) {                  
..............                  
                    
  if (!allDrawn && w.mightAffectAllDrawn()) {                   
            if (DEBUG_VISIBILITY || DEBUG_ORIENTATION) {                    
                Slog.v(TAG, "Eval win " + w + ": isDrawn=" + w.isDrawnLw()                  
                        + ", isAnimationSet=" + isSelfAnimating());                 
                if (!w.isDrawnLw()) {                   
                    Slog.v(TAG, "Not displayed: s=" + winAnimator.mSurfaceController                    
                            + " pv=" + w.isVisibleByPolicy()                    
                            + " mDrawState=" + winAnimator.drawStateToString()                  
                            + " ph=" + w.isParentWindowHidden() + " th=" + hiddenRequested                  
                            + " a=" + isSelfAnimating());                   
                }                   
            }                   
        

Kindly let me know how to redirect to homescreen when home button is pressed during blank screen or white screen.