How to Obtain IP Address of Connected Client in xinetd Custom Service

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Question: xinetd (extended Internet services daemon) maps input to a service's standard input and output to a service's standard out.

In other words, assuming a custom TCP service written in C, data coming into port X is mapped to stdin of the service and stdout of the service is mapped to data coming out of port Y.

Again, assuming a custom TCP service written in C, is there a way for that service to determine the connecting client's IP Address?

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FOLLOW UP NOTE: xinetd takes the socket descriptor associated with TCP port X and maps it to the service's standard input.

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Yes, with getpeername(2) on its stdin (0) or stdout (1) file descriptor.

Example: when run from xinetd or inetd, this will print the address of the client connected to its stdin:

#define _DEFAULT_SOURCE
#include <unistd.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netinet/in.h>
#include <stdio.h>
#include <err.h>
#include <netdb.h>

int main(void){
        union {
                struct sockaddr a;
                struct sockaddr_in in;
                struct sockaddr_in6 in6;
        } na;
        char host[NI_MAXHOST], port[NI_MAXSERV]; int e;
        socklen_t nl = sizeof na;
        if(getpeername(0, &na.a, &nl)) err(1, "getpeername");
        if(e = getnameinfo(&na.a, nl, host, sizeof host, port, sizeof port,
                        NI_NUMERICHOST|NI_NUMERICSERV))
                errx(1, "getnameinfo: %s", gai_strerror(e));
        switch(na.a.sa_family){
        case AF_INET:
                errx(0, "connection from %s:%s", host, port);
        case AF_INET6:
                errx(0, "connection from [%s]:%s", host, port);
        default:
                errx(0, "connection from unknown address family %d",
                        na.a.sa_family);
        }
}