How to use globs to not do an action on a file? (Gulp)

Question

I'm using gulp with gulp-if, gulp-babel, and gulp-uglify, my intent is to not run babel or uglify on minified JS files since the minified files are all lib/vendor files that don't need to be processed. However, they do need to be moved over into the new folder.

Here's what I've got:

.pipe($.if(!/(.min.js)/g,
  $.babel({
     presets: ['es2015']
  })
 ))
.pipe($.if(!/(.min.js)/g,
   $.uglify()
))

I don't think the rest of the context is too important, so I left it out.

The issue that I'm having currently is that the expression isn't working, I guess I wasn't clear on the syntax of how gulp-if works.

What is the best way to do this?

Answer 1

I was able to figure it out..

I replaced .pipe($.if(/.min.js/g, with .pipe($.if(match,

Then created the match function..

function match(file) {
    if (file.path.match(/.min.js/g)) {
        return false;
    } else {
        return true;
    }
}

Now it works as expected!

Please let me know if there is an easier/better way to do this!