I'm trying to make two child processes communicate with each other via pipe.First child have to write data 1 and data 2, and then second child writes data 3 and data 4. Then childrens read each other data and print them. This is the code that i have so far. It only displays the first messages children sends to each other and than it hangs.
#include <stdio.h>
#include <sys/types.h>
int main(void) {
pid_t child_a, child_b;
int pipe_a[2],pipe_b[2];
char mesazhi1[] = "First message";
char mesazhi2[] = "Second message";
char buf[50];
int first_pipe = pipe(pipe_a);
int second_pipe = pipe(pipe_b);
if(first_pipe == -1 || second_pipe == -1 ){
perror("pipe");
exit(1);
}
child_a = fork();
if (child_a == 0) {
/* Child A code */
printf("%s\n","the first child is writing to pipe a" );
write(pipe_a[1],mesazhi1, sizeof(mesazhi1));
write(pipe_a[1],mesazhi2,sizeof(mesazhi2));
while( read(pipe_b[0],buf,sizeof(buf) + sizeof(buf) ) > 0 ){
printf("Reading from buffer for child 1 gives: %s \n",buf);
}
} else {
child_b = fork();
if (child_b == 0) {
/* Child B code */
printf("%s\n","the second child is writing to pipe b" );
write(pipe_b[1],mesazhi2,sizeof(mesazhi2));
while( read(pipe_a[0],buf,sizeof(buf) +sizeof(buf) ) > 0 ){
printf("Reading from buffer for child 2 gives: %s \n",buf);
}
write(pipe_b[1],mesazhi1,sizeof(mesazhi1));
printf("%s\n","the second child reads data from pipe a" );
} else {
/* Parent Code */
int returnStatusA,returnStatusB;
waitpid(child_a, &returnStatusA, 0); // Parent process waits here for child to terminate.
waitpid(child_b, &returnStatusB, 0); // Parent process waits here for child to terminate.
if (returnStatusA == 0 && returnStatusB == 0) // Verify child process terminated without error.
{
printf("%s\n", "The child processes terminated normally.\n");
}
if (returnStatusA == 1 && returnStatusB == 1)
{
printf("%s\n", "The child processes terminated with an error!. \n" );
}
printf("%s\n","The parent terminates two childs");
}
}
}
Your code causes a deadlock.
You're using
read()
function in a wrong way.read(pipe_a[0],buf,sizeof(buf) +sizeof(buf) )
You expect twice of size of your buffer and want to put that amount of bytes in your buffer. So
read
in child A waits forpipe_b
and vice versa. Therefore child B can't write topipe_b
because it's waiting.Similarly, child A can't write inpipe_a
because it's waiting.Additionally, Your code is not same as the scenario you explained in your question. In child B you are writing after reading.
And finally use
strlen()
for calculating length of strings instead ofsizeof
.