Identify if a column is Virtual in Snowflake

Question

Snowflake does not document its Virtual Column capability that uses the AS clause. I am doing a migration and needing to filter out virtual columns programatically.

Is there any way to identify that a column is virtual? The Information Schema.COLLUMNS view shows nothing different between a virtual and non-virtual column definition.

Answer 1

How about using SHOW COLUMNS ? you should identify them when expression field is not null.

create table foo (id bigint, derived bigint as (id * 10));
insert into foo (id) values (1), (2), (3);

SHOW COLUMNS IN TABLE foo;
SELECT "table_name", "column_name", "expression" FROM table(result_scan(last_query_id()));

| table_name | column_name | expression     |
| ---------- | ----------- | -------------- |
| FOO        | ID          | null           |
| FOO        | DERIVED     | ID*10          |

Answer 2

There is a difference between column defined as DEFAULT and VIRTUAL COLUMN(aka computed, generated column):

Virtual column

CREATE OR REPLACE TABLE T1(i INT, calc INT AS (i*i));
INSERT INTO T1(i) VALUES (2),(3),(4);
SELECT * FROM T1;

When using AS (expression) syntax the expression is not visible inCOLUMN_DEFAULT:

---

DEFAULT Expression

In case of the defintion DEFAULT (expression):

CREATE OR REPLACE TABLE T2(i INT, calc INT DEFAULT (i*i));
INSERT INTO T2(i) VALUES (2),(3),(4);
SELECT * FROM T2;

It is visible in COLUMN_DEFAULT:

SELECT * 
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'T2';

---

Comparing side-by-side with SHOW COLUMNS:

SHOW COLUMNS LIKE 'CALC';
-- kind: VIRTUAL_COLUMN

One notable difference between them is that virtual column cannot be updated:

UPDATE T1
SET calc  = 1;
-- Virtual column 'CALC' is invalid target.

UPDATE T2
SET calc = 1;
-- success

Answer 3

I normally use the desc table option.

First lets create the table with some example data:

create or replace temporary table ColumnTypesTest (
    id int identity(1,1) primary key,
    userName varchar(30),
    insert_DT datetime default CAST(CONVERT_TIMEZONE('UTC', CAST(CURRENT_TIMESTAMP() AS TIMESTAMP_TZ(9))) AS TIMESTAMP_NTZ(9)) not null,
    nextDayAfterInsert datetime as dateadd(dd,1,insert_DT)
);

insert into ColumnTypesTest (userName) values
('John'),
('Cris'),
('Anne');

select * from ColumnTypesTest;

ID	USERNAME	INSERT_DT	NEXTDAYAFTERINSERT
1	John	2021-10-04 19:11:21.069	2021-10-05 19:11:21.069
2	Cris	2021-10-04 19:11:21.069	2021-10-05 19:11:21.069
3	Anne	2021-10-04 19:11:21.069	2021-10-05 19:11:21.069

Now the answer to your question

Using the 'desc table <table_name>;' you will get a column named kind which will tell you if it is virtual or not, also separately there is the default with NULL if it has no default value.

name	type	kind	null?	default	primary key	unique key	check	expression	comment	policy name
ID	NUMBER(38,0)	COLUMN	N	IDENTITY START 1 INCREMENT 1	Y	N
USERNAME	VARCHAR(30)	COLUMN	Y		N	N
INSERT_DT	TIMESTAMP_NTZ(9)	COLUMN	N	CAST(CONVERT_TIMEZONE('UTC', CAST(CURRENT_TIMESTAMP() AS TIMESTAMP_TZ(9))) AS TIMESTAMP_NTZ(9))	N	N
NEXTDAYAFTERINSERT	TIMESTAMP_NTZ(9)	VIRTUAL	Y		N	N		DATE_ADDDAYSTOTIMESTAMP(1, INSERT_DT)

A/ With 'desc table <table_name>' you get meta data of the table with a column named kind, which will say VIRTUAL or COLUMN. In case it is VIRTUAL, then in the column expression you get how that column is calculated.

This is used in Stored Procedures, and saved in an array of arrays with javascript, from there the next query in the stored procedure is created dynamically. A while loop is used to go through the resultSet and push each row intho the array of arrays. You can then use javascript filter to just get the virtual columns. This is part of the advantage of having a mix of javascript and SQL in Snowflake Stored Procedures.

Here the documentation which doesn't say much.