Implementation of transcoding using only bitwise operators

Question

I have function to transcode input hexadecimal number. For example I have initial format of number like this

And function transcodes it to this format:

I will return result from function as a string using hex built-in function. I tried something like this, but that didn't work:

def task22(number) -> str:
    """
    Returns transcoded hexadecimal string, this function uses bitwise operators to transcode given value
    :param number: hexadecimal number to transcode
    :return: Transcoded hexadecimal string
    """
    a = number & 0b111111111111111
    b = number & 0b111111111111111
    c = number & 0b11
    a = a << 17
    b = b >> 13
    c = c >> 30

    return hex(a | b | c)

How can I use bitwise operators to transcode number? I need to use bitwise shifts to the left and right but I have no idea how to do it for formats described above.

Answer 1

Solved. The problem was I needed to process all segments using bitwise AND operator with 32 zeros (because number of all bits is 32) replaced by 1 where each segment is located in the sequence of bits like this:

def task22(number) -> str:
    """
    Returns transcoded hexadecimal string, this function uses bitwise operators to transcode given value
    :param number: hexadecimal number to transcode
    :return: Transcoded hexadecimal string
    """
    a = number & 0b00000000000000000111111111111111
    b = number & 0b00111111111111111000000000000000
    c = number & 0b11000000000000000000000000000000
    a = a << 17
    b = b >> 13
    c = c >> 30

    return hex(a | b | c)