Result<T, E>.as_ref()
will convert it to Result<&T, &E>
, but the expected result is Result<&T, E>
.
Is there a simple way to get Result<&T, E> from Result<T, E>?
103 Views Asked by progquester At
1
There are 1 best solutions below
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If you want to place conversion in a function, the function will have to take the Result by reference. This is because, in order to use
&T
in the result type, there must be a reference in at least one of the arguments (so that the returned reference can have a lifetime). This will pose the problem in theErr
case in which you'd ideally want to consume the original Result, but aren't allowed to do so because you get it by reference. If you can get away with requiringE: Clone
, then this will work:Another possibility is to require
E
to implementDefault
, in which case you could extract theErr(e)
from the originalResult
and leave the default in its place:If you don't need to extract conversion in a function, but just want to transform the Result in-place, then you don't need to require any traits of
E
. You can either consume the result or not depending on a condition, and borrow checker will allow it. The code is then as simple as: