Last day of a month or a year in XSLT

Question

i'm having some issues to make this work on a transformation in Oracle Bpel I receive a date, and a group criteria: mm/yyyy or: yyyy.

So, I have to construct an 'start day' and an 'end date' with the date I receive.

if the criteria is mm/yyyy, the start day will be the first day of the given month/year, and the end date, the last day of the given month/year.

I know there is a function called: functx:last-day-of-month

But I cannot make this work in Oracle Bpel, so that's why i'm using this answer: Last day of previous month in XSLT Just want to know how to do that with any given month.

Example: for the given date: 2012-10-20T20:18:33

I should return the dates:

Start date: 2012-10-01

End date: 2012-10-31

Thanks a lot for any help.

Answer 1

If your processor supports only XSLT 1.0, you can determine the last day of month of any given date by calling the following named template:

<xsl:template name="last-day-of-month">
    <xsl:param name="date"/>
    <xsl:param name="y" select="substring($date, 1, 4)"/>
    <xsl:param name="m" select="substring($date, 6, 2)"/>
    <xsl:param name="cal" select="'312831303130313130313031'"/>
    <xsl:param name="leap" select="not($y mod 4) and $y mod 100 or not($y mod 400)"/>
    <xsl:param name="month-length" select="substring($cal, 2*($m - 1) + 1, 2) + ($m=2 and $leap)" />
    <xsl:value-of select="concat($y, '-', $m, '-', $month-length)" />
</xsl:template>

Example call:

<output>
    <xsl:call-template name="last-day-of-month">
        <xsl:with-param name="date">2012-10-20T20:18:33</xsl:with-param>
    </xsl:call-template>
</output>

returns:

<output>2012-10-31</output>      

Example call:

<output>
    <xsl:call-template name="last-day-of-month">
        <xsl:with-param name="date">2012-02-15</xsl:with-param>
    </xsl:call-template>
</output>

returns:

<output>2012-02-29</output>

---

Added:

For completion, in XSLT 2.0 you can do:

xs:date($given-date) - xs:dayTimeDuration(concat('P', day-from-date($given-date) - 1, 'D')) + xs:yearMonthDuration('P1M') - xs:dayTimeDuration('P1D')