Need numbering above each column of a python grid

Question

I need to modify a program the program 'x' so that it outputs the original grid, but each row and column is labeled with it's respective number. i.e. column 1 has a first, row 1 has a 1 first. I have figured out how to put numbering in front of the rows, but cannot figure out how to modify the program so that the columns are numbered.

'x'

import random
aGrid = []
SIZE = 10
for r in range (0,SIZE,1):
    aGrid.append ([])
    for c in range (0,SIZE,1):
        element = random.randint(0,9)
        aGrid[r].append (element)
for r in range (0,SIZE,1):
    for c in range (0,SIZE,1):
        print(aGrid[r][c], end="")
    print()

Here is my attempt at getting numbering in front of the rows

import random
aGrid = []
SIZE = 11

for r in range (0,SIZE - 1,1):
    aGrid.append ([])
    aGrid[r].append (r )
    aGrid[r].append (" ")
    for c in range (0,SIZE + 1,1):
        element = random.randint(0,9)
        aGrid[r].append (element)

for r in range (0,SIZE - 1,1):
    for c in range (0,SIZE + 1,1):
        print(aGrid[r][c], end="")
    print()

Answer 1

You don't need to change aGrid. Just print the row and column numbers in the print loop:

import random

aGrid = []
SIZE = 10

for r in range (SIZE):
    aGrid.append ([])
    for c in range (SIZE):
        element = random.randint(0,9)
        aGrid[r].append (element)
print(" ", end="")
for c in range (SIZE):
    print(c, end="")
print()
for i, r in enumerate(range(SIZE)):
    print(i, end="")
    for c in range(SIZE):
        print(aGrid[r][c], end="")
    print()

Output:

 0123456789
01958724133
17006217440
21488953544
35615572045
49849348546
54207744418
63316678723
76651582077
85713263320
91939404287

A version that starts counting from 1 and has some spaces for better readability:

import random

aGrid = []
SIZE = 10

for r in range (SIZE):
    aGrid.append ([])
    for c in range (SIZE):
        element = random.randint(0,9)
        aGrid[r].append (element)
print("  ", end=" ")
for c in range (1, SIZE + 1):
    print(c, end=" ")
print()
for i, r in enumerate(range(SIZE), 1):
    print('{:2d}'.format(i), end=" ")
    for c in range(SIZE):
        print(aGrid[r][c], end=" ")
    print()

Output:

   1 2 3 4 5 6 7 8 9 10 
 1 3 0 4 6 3 9 3 3 6 3 
 2 5 6 1 6 6 3 2 5 6 1 
 3 6 9 0 5 0 7 1 1 7 7 
 4 7 4 3 9 0 9 1 0 7 8 
 5 5 1 1 1 1 7 1 4 4 8 
 6 4 5 8 1 6 3 6 2 8 6 
 7 4 1 0 5 7 4 5 6 6 4 
 8 4 5 5 4 3 3 0 9 2 1 
 9 3 6 7 0 0 9 5 8 5 9 
10 3 1 2 3 5 0 1 6 2 9