I have a model with a field occupation_area as a choice
class Vacancy(models.Model):
name = models.CharField('Name', max_length=255)
occupation_area = models.CharField(
'Occupation area',
max_length=3,
choices=OCCUPATION_AREA_CHOICES
)
and i have a filter area in my index that contains this field like "Occupation" which works fine
now, i have that's detail pages like above, and in those i have a link that must be taken to the index and pass the name of the occupation as a parameter to be filtered only something with these occupations
i tried this in the url:
<a href="{% url 'vacancies:vacancy_search' vacancy.get_occupation_area_display %}">Link</a>
but apresents this error, this is just a problem with the way i am passing the url??:


It's difficult to say without the related view & url file. However there is somtehing wrong in the url. It should be:
being "a" the variable declared in the correspondent path in the urls.py file:
for example.