Register services with child interface type using Scrutor

Question

I have the following interfaces:

public interface IValidator
{
    Task<Response> Validate(object request);
}

public interface IFirstChildValidator : IValidator

public interface ISecondChildValidator : IValidator

I have some services that implement the first and the second validators.

Before using Scrutor, I registered the services manually, and everything worked as expected:

services.AddScoped<IFirstChildValidator, FirstBar>();
services.AddScoped<IFirstChildValidator, FirstFoo>();

services.AddScoped<ISecondChildValidator, SecondBar>();
services.AddScoped<ISecondChildValidator, SecondFoo>();

and I could inject a specific validator to my other services:

private readonly IEnumerable<IFristValidator> _firstValidators;
// ctor injection

However, when I try to auto-register (the first validator as an example) using Scrutor:

services.Scan(scan => scan
    .FromAssemblyOf<IFirstChildValidator >()
    .AddClasses(classes => classes
        .InNamespaces("my.namespace")
        .AssignableTo<IFirstChildValidator>())
    .UsingRegistrationStrategy(RegistrationStrategy.Replace(ReplacementBehavior.ImplementationType))
.AsImplementedInterfaces()
.WithScopedLifetim();

The injected type is the parent validator (i.e. IValidator), and the injected array of the specific implementation is left empty.

How can I achieve auto-register as specific interfaces as types?

Answer 1

You must remove the UsingRegistrationStrategy this defines how to handle duplicates, in your case you want ALL of its implementations.

You can also replace it with .UsingRegistrationStrategy(RegistrationStrategy.Append)

services.Scan(scan => scan
    .FromAssemblyOf<IFirstChildValidator>()
    .AddClasses(classes => classes
        .InNamespaces("my.namespace")
        .AssignableTo<IFirstChildValidator>())
.AsImplementedInterfaces()
.WithScopedLifetime());

Here a .NET FIddle