Send function to call() as argument

Question

here in this example

function a() { console.log(this.x); }

var x = 10;
a.x = 20;

a.call(a);

The result is 20

Why does this happen?

I know in call method we can send object but here send a function? can we do that? and why does a.x work?

Answer 1

The call() method can be used to invoke a function with a specific this value, which can be an object or any other value.

In this example, a.x works because functions in JavaScript are also objects and can have properties added to them. So, a.x adds a property x to the function a.