Unable to pass password with space to shell script

Question

I have below script which turns on the tether mode on my intel edison. But when I entered password with space it shows error that argument list is long. Without space it works perfectly fine

#!/usr/bin/env bash

SSID_FILE="/usr/share/apache2/htdocs/userhotspotname.conf"
if [ -s "$SSID_FILE" ]
then
    filename="/usr/share/apache2/htdocs/userhotspotname.conf"
    while IFS= read -r line; do
        if [[ $line == hotspotna* ]] ; then
            name=$(echo $line | grep "hotspotname" | cut -d= -f2)

        fi
        if [[ $line == hotspotpa* ]] ; then
            pass=$(echo $line | grep "hotspotpass" | cut -d= -f2)
            #pass="'${pass}'"
            echo $pass
        fi
        done < "$filename"
        **connmanctl tether wifi on "${name}" ${pass}**
fi

Below is userhotspotname.conf file content

hotspotname=cvg_space
hotspotpass=cgoma  pwd space

Since password is with space connmanctl tether wifi on "${name}" ${pass} This command is failing since it is considering it as 4 arguments. Please help in this if anyone has idea.