Using scala spark how to print just the response body value returned from a HTTP post call

Question

I have a flask application that returns the following if I do a cURL to it:

The response is in a JSON format as follows:

{"your_field": "hello there buddy"}

I want to get just the value "hello there buddy" and print it. Any idea how to do it?

I have the following code:

def myExampleFunction  = ( text: String ) => {

  val result = Http("http://localhost:5001/other/post").postData("{\"my_field\":\"" + text + "\"}")
    .header("Content-Type", "application/json")
    .header("Charset", "UTF-8")
    .option(HttpOptions.readTimeout(10000)).asString

  println("result.body is!! : " + result.body)
  result.body

Running this prints the following:

result.body is!! : {"your_field": "hello there buddy"}

What I want to achieve is:

result.body is!! : hello there buddy

Answer 1

result.body is of type string, parse string data to json data to extract the required field.

In below code I have used json4s library to parse string response to json data.

  def myExampleFunction  = ( text: String ) => {
    import org.json4s._
    import org.json4s.native.JsonMethods._
    implicit val formats = DefaultFormats

    val result = Http("http://localhost:5001/other/post")
      .postData("{\"my_field\":\"" + text + "\"}")
      .header("Content-Type", "application/json")
      .header("Charset", "UTF-8")
      .option(HttpOptions.readTimeout(10000))
      .asString

    (parse(result.body) \\ "your_field").extract[String]
}