Im am working on a VHDL project that includes an fsm. Some states change according to a counter. It dit not work until i put 'clk' in the sensitivity list, besides the current state and the input. I know that during synthesis, the sensitivity not used, or discarded. But how can that have such an impact on the result in the simulation? if a leave this 'clk', would the fsm perform as i want op an FPGA?
thanks,
David
This is the simple explanation:
The simulator uses the sensitivity list to figure out when it needs to run the process. The reason why the simulator needs hints to figure out when to run the process is because computer processors can only do one (or only a few in multicore systems) thing at a time and the processor will have to take turns running each part of your design. The sensitivity list allows simulation to run in a reasonable time frame.
When you synthesize code into an ASIC or FPGA, the process is always "running" since it has dedicated hardware.
When you simulate a state machine without the clock in the sensitivity list, the process will never run on the clock edges, but only on changes to your input. If you have the state transition implemented as a flip flop (if clk'event and clk = '1') then your state transition will never be simulated unless you happen to change your input at the same time as the clock's rising edge. You should probably leave the clock in the sensitivity list, assuming the FSM changes on clock edges.
Also, try to proofread your questions.