I'm trying to understand async workflows in F# but I found one part that I really don't understand.
The following code works fine:
let asynWorkflow = async{
let! result = Stream.TryOpenAsync(partition) |> Async.AwaitTask
return result
}
let stream = Async.RunSynchronously asynWorkflow
|> fun openResult -> if openResult.Found then openResult.Stream else Stream(partition)
I define a async workflow where TryOpenAsync returns a Task<StreamOpenResult> type. I convert it to Async<StreamOpenResult> with Async.AwaitTask. (Side quest: "Await"Task? It doesn't await it just convert it, does it? I think it has nothing to do with Task.Wait or the await keyword). I "await" it with let! and return it.
To start the workflow I use RunSynchronously which should start the workflow and return the result (bind it). On the result I check if the Stream is Found or not.
But now to my first question. Why do I have to wrap the TryOpenAsync call in another async computation and let! ("await") it? E.g. the following code does not work:
let asynWorkflow = Stream.TryOpenAsync(partition) |> Async.AwaitTask
let stream = Async.RunSynchronously asynWorkflow
|> fun openResult -> if openResult.Found then openResult.Stream else Stream(partition)
I thought the AwaitTask makes it an Async<T> and RunSynchronously should start it. Then use the result. What do I miss?
My second question is why is there any "Async.Let!" function available? Maybe because it does not work or better why doesn't it work with the following code?
let ``let!`` task = async{
let! result = task |> Async.AwaitTask
return result
}
let stream = Async.RunSynchronously ( ``let!`` (Stream.TryOpenAsync(partition)) )
|> fun openResult -> if openResult.Found then openResult.Stream else Stream(partition)
I just insert the TryOpenAsync as a parameter but it does not work. By saying does not work I mean the whole FSI will hang. So it has something to do with my async/"await".
--- Update:
Result of working code in FSI:
>
Real: 00:00:00.051, CPU: 00:00:00.031, GC gen0: 0, gen1: 0, gen2: 0
val asynWorkflow : Async<StreamOpenResult>
val stream : Stream
Result of not working code in FSI:
>
And you cannot execute anything in the FSI anymore
--- Update 2
I'm using Streamstone. Here the C# example: https://github.com/yevhen/Streamstone/blob/master/Source/Example/Scenarios/S04_Write_to_stream.cs
and here the Stream.TryOpenAsync: https://github.com/yevhen/Streamstone/blob/master/Source/Streamstone/Stream.Api.cs#L192
The second code block looks like it should work to me. It does run it if I provide dummy implementations for
StreamandStreamOpenResult.You should avoid using
Async.RunSynchronouslywherever possible because it defeats the purpose of async. Put all of this code within a largerasyncblock and then you will have access to theStreamOpenResult:You may need to put a
Async.StartorAsync.RunSynchronouslyat the very outer edge of your program to actually run it, but it's better if you have theasync(or convert it to aTask) and pass it to some other code (e.g. a web framework) that can call it in a non-blocking manner.