why does C++ allow a declaration with no space between the type and a parenthesized variable name?

Question

A previous C++ question asked why int (x) = 0; is allowed. However, I noticed that even int(x) = 0; is allowed, i.e. without a space before the (x). I find the latter quite strange, because it causes things like this:

using Oit = std::ostream_iterator<int>;
Oit bar(std::cout);
*bar = 6;  // * is optional
*Oit(bar) = 7;  // * is NOT optional!

where the final line is because omitting the * makes the compiler think we are declaring bar again and initializing to 7.

Am I interpreting this correctly, that int(x) = 0; is indeed equivalent to int x = 0, and Oit(bar) = 7; is indeed equivalent to Oit bar = 7;? If yes, why specifically does C++ allow omitting the space before the parentheses in such a declaration + initialization?

(my guess is because the C++ compiler does not care about any space before a left paren, since it treats that parenthesized expression as it's own "token" [excuse me if I'm butchering the terminology], i.e. in all cases, qux(baz) is equivalent to qux (baz))

Answer 1

One requirement when defining the syntax of a language is that elements of the language can be separated. According to the C++ syntax rules, a space separates things. But also according to the C++ syntax rules, parentheses also separate things.

When C++ is compiled, the first step is the parsing. And one of the first steps of the parsing is separating all the elements of the language. Often this step is called tokenizing or lexing. But this is just the technical background. The user does not have to know this. He or she only has to know that things in C++ must be clearly separted from each others, so that there is a sequence "*", "Oit", "(", "bar", ")", "=", "7", ";".

As explained, the rule that the parenthesis always separates is established on a very low level of the compiler. The compiler determines even before knowing what the purpose of the parenthesis is, that a parenthesis separates things. And therefore an extra space would be redundant.

When you ever use parser generators, you will see that most of them just ignore spaces. That means, when the lexer has produced the list of tokens, the spaces do not exist any more. See above in the list. There are no spaces any more. So you have no chance to specify something that explicitly requires a space.

Answer 2

It is allowed in C++ because it is allowed in C and requiring the space would be an unnecessary C-compatibility breaking change. Even setting that aside, it would be surprising to have int (x) and int(x) behave differently, since generally (with few minor exceptions) C++ is agnostic to additional white-space as long as tokens are properly separated. And ( (outside a string/character literal) is always a token on its own. It can't be part of a token starting with int(.

In C int(x) has no other potential meaning for which it could be confused, so there is no reason to require white-space separation at all. C also is generally agnostic to white-space, so it would be surprising there as well to have different behavior with and without it.