Writing a one liner code that outputs filenames with more than 10 characters and whose content has more than 10 lines

Question

Thank you all for the help before. I now had completed a task (so I thought) in order to achieve the following: I needed to write a one liner which outputs filenames that have more than 10 characters and also their contents consists out of more than 10 lines. My code is the following:

import os; [filename for filename in os.listdir(".") if len(filename) > 10 and len([line for line in open(filename)]) > 10 if filename =! filename.endswith(".ipynb_checkpoints")]

The problem that exists is the following error:

[Errno 13] Permission denied: '.ipynb_checkpoints'

I tried to exclude the .ipynb_checkpoint-files but it still doesn´t work properly. Do you have any suggestions on how to exclude them or solve my problem? Thank you for your time!

Greetings.

Answer 1

The issue might be the order of your if statements, String.ends with returns a boolean and cannot be compared to the string, and __pycache__ files also cause errors so I added it.

Some of the characters in ipynb files cause UnicodeDecodeError: 'charmap' codec can't decode errors and decoding in Latin-1 seemed to fix that. (UnicodeDecodeError: 'charmap' codec can't decode byte X in position Y: character maps to <undefined>)

you could try something like:

import os; print([filename for filename in os.listdir(".") if not filename.endswith(".ipynb_checkpoints") and not filename.endswith("__pycache__") and len(filename) > 10 and len([line for line in open(filename, encoding="Latin-1")]) > 10])

this solution seems to work but maybe a more general solution makes more sense.ie: PermissionError: [Errno 13] Permission denied