I know that MARIE's instruction set has 16-bit per instruction, given that there are 9 instructions, doesn't it make sense that 16*9 = 144bits are needed to store all of the instruction? But apparently its wrong, whats wrong with my reasoning and can you guide me to the answer?
How many bits are required to store MARIE's instruction set?
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I think you are looking for the following data structure
as Paul R and Peter Cordes already mentioned in his comments.