I read example in http://www.w3schools.com/json/json_example.asp.
And I try it with my MySQL database and my PHP code. But it does not work. I am a beginner and I don't know what it wrong.
Here is my PHP link: http://xebus2014.tk/demo.php
And I change w3school code like this:
<!DOCTYPE html>
<html>
<head>
<style>
h1 {
border-bottom: 3px solid #cc9900;
color: #996600;
font-size: 30px;
}
table, th , td {
border: 1px solid grey;
border-collapse: collapse;
padding: 5px;
}
table tr:nth-child(odd) {
background-color: #f1f1f1;
}
table tr:nth-child(even) {
background-color: #ffffff;
}
</style>
</head>
<body>
<h1>Customers</h1>
<div id="id01"></div>
<script>
var xmlhttp = new XMLHttpRequest();
var url = "http://xebus2014.tk/demo.php";
xmlhttp.onreadystatechange=function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
myFunction(xmlhttp.responseText);
}
}
xmlhttp.open("GET", url, true);
xmlhttp.send();
function myFunction(response) {
var arr = JSON.parse(response);
var i;
var out = "<table>";
for(i = 0; i < arr.length; i++) {
out += "<tr><td>" +
arr[i].STT +
"</td><td>" +
arr[i].ID +
"</td><td>" +
arr[i].Name +
"</td><td>" +
arr[i].Singer +
"</td></tr>";
}
out += "</table>"
document.getElementById("id01").innerHTML = out;
}
</script>
</body>
</html>

Did you set the response as Json String?