Intel-TSX: why rtm is acting weird?

Question

I have the following code using Intel-rtm,

rtmCheck.c:

#include <stdio.h>
#include <stdlib.h>
#include <immintrin.h>

int test_otherfunction(int a, int b){
int c=0;
   
for (int i=0; i<1000;i++){
      c=c+a+b;
   }


for (int i=0; i<1000000000;i++){
    c=c+a+b;
}

for (int i=0; i<1000000000;i++){
    c=c+a+b;
}
for (int i=0; i<1000000000;i++){
    c=c+a+b;
}

return 1;
}

int main(int argc, char *argv[])
{
   int result=-1;
   unsigned status;
   while(result!=1){
      if ((status = _xbegin()) == _XBEGIN_STARTED) {
         if(test_otherfunction(1,2))
             result=1;
             _xend();
      }else{
             printf("rtmCheck: Transaction failed\n");
             printf("status is %ld\n", status);
             printf("Trying again ...\n");

      }
    
   }
printf("rtmCheck : Result is %d\n", result);

return 0;
}

If I compile with the following Makefile1, It always failed. I guess that is expected. And I'm okay with it.

Makefile1

CC=gcc
CFLAGS= -mrtm

rtmCheck: rtmCheck.o
        $(CC) $(CFLAGS) -o rtmCheck rtmCheck.o

clean: 
        rm -f *.o rtmCheck

Output:

rtmCheck: Transaction failed
status is 0
Trying again ...
rtmCheck: Transaction failed
status is 0
Trying again ...
rtmCheck: Transaction failed
status is 0
Trying again ...
...........
...........

But I have another Makefile2. If I compile my code with this(Makefile2) this works every time. just not understanding why?

Makefile2:

CC  := gcc
CFLAGS  :=  -mrtm -Wall -g -MD -O2 -I ../
LDFLAGS := -ltest 

tests_files := rtmCheck

all: $(tests_files)

rtmCheck: rtmCheck.o ../libtest/libtest.a
        $(CC) $(CFLAGS) -static $(<) -L../libtest/ $(LDFLAGS) -o $(@)

clean:
        rm -f *.o test *.d $(tests_files)

-include *.d

OutPut:

$./rtmCheck 
rtmCheck : Result is 1

Above Make file use some static library. But I'm not using anything from the library. Can someone please tell me why this is happening?