Assume a computer with a 16-bit memory and 16-bit data and address bus. So if an Instruction is of 16-bit let's say the opcode occupies 6 bits and the operand occupies the remaining 10 bits. In the direct addressing mode, the memory address of the operand is specified in the instruction itself. So how a 16-bit memory location is specified inside the 10-bit instruction operand. Is the address encoded somehow or one Instruction is stored in multiple memory locations? Sorry, If my question seems kind of stupid.
Instruction format in direct addressing mode
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